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Consider the circuit shown in the diagram, find (A) the current in the 2.00 Ω resistor, (B) the current in the 6.00 Ω resistor, and (C) the potential difference between points *a* and *b *). Identify the current directions as to the right or to the left.

Doing a little rearrangement, we have the following circuit diagram:

At node b, we have ||I_1=I_3+I_2||.

For the two loops, we have $$12-4I_1-2I_3=0$$ and $$8+2I_3-6I_2=0$$

Solve for for the ||I||'s.

Then we can find ||V_{ab}=2I_3||.